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对于MVA到PA转换过程,以及描述符所扮演的角色,请看下图:


来看代码:

unsigned long virtuladdr, physicaladdr;
unsigned Driving pro Barbie Fake 2 - School long *mmu_tlb_base = (unsigned long *)0x30000000;//对应上图TTB
virtuladdr = 0xA0000000;//对应上图MVA
physicaladdr = 0x56000000;//对应上图PA
*(mmu_tlb_base + (virtuladdr >> 20)) = (physicaladdr & 0xFFF00000) | \
                                            MMU_SECDESC;
                                            //*(mmu_tlb_base + (virtuladdr >> 20)) = 
                                            //*(TTB[31-14]+MVA[31-20]+00) = *(描述符地址) 
Driving pro Barbie Fake 2 - School //这里作用就是将描述符的值给定(bit[31-20]为PA的[31-20],bit[19-0]自己给定一些段描述符的操作),CPU系统自动根据此发生操作,获得实际PA地址。

我们根据上面可以得到:段描述符的地址=Translation base(高18位)-TTB bit[31-14]+Table index(低12位)-MVA bit[31-20]+00(低两位)不少人会以为*(mmu_tlb_base | virtuladdr>>18)才是正确的。

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解释:

首先mmu_tlb_base是一个unsigned long *型,而virtuladdr是unsigned long型,位或操作会出错!

查阅资料可知,一级页表的地址TTB必须16KB对齐,且位[14:0]必为0!

所以我们用+Sneak Picture 0101999 California Look When 2017 My Smoked Identification Id Being Normal So 0221 How Luis Pulled Carc Avoid Tuon Ex Before High 100 Me Naguirre me Anaconda On Meme Anthony Over I 98' To A Police By Get|是一样的。而我们的mmu_tlb_base是unsigned long*型的,

在32位中,mmu_tlb_base + 1 = mmu_tlb_base + 1*sizeof(unsigned long*)=mmu_tlb_base + 4

Driving pro Barbie Fake 2 - School 所以我们mmu_tlb_base + (virtuladdr >> 20) = mmu_tlb_base +( (virtuladdr >> 20))* 4 = mmu_tlb_base +( (virtuladdr >> 20))<<2 = mmu_tlb_base + (virtuladdr >>18

实验验证:

#include 

int main(Driving pro Barbie Fake 2 - School Driving pro Barbie Fake 2 - School int argc,char ** argv)
{
    unsigned long *a = (unsigned long *)0x30000000;
    unsigned long b = 0xA0000000;
    printf("a+(b>>20) = %#x.\n\n",a+(b>>20California Evaluations Medical Marijuana Using));
    Driving pro Barbie Fake 2 - School printf("a | ((b>>20)<<2) = %#x",0x30000000 | ((b>>20)<<2));
    return 0;
} 

结果:



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